A
albert_roca
I am developing a geometric model of physical interactions based on geometric constraints (w = 2, δ = √5 ) and topological invariants. No free parameters, just geometry. In your opinion, is this a legitimate geometric unification or just sophisticated curve-fitting?
Results:
Proton radius (r_p): Modeled as a tetrahedral structural limit (4 · ƛ) with spherical field projection loss (α / 4 · π).
Proton magnetic moment (g_p): Derived from the dynamic potential (δ = √5 ) damped by a golden friction term (α / Φ).
Muon anomaly (a_μ): Derived as a hierarchical resolution of the icosahedral geometry: surface (α / 2 · π) + nodes (α^2 / 12) + vertex symmetry (α^3 / 5).
α particle radius (r_α): Modeled as a 4-nucleon tetrahedron (8 · ƛ) with a linear nucleonic projection cost (α / π).
Proton mass (m_p): Connecting the Planck scale to proton scale via a 64-bit metric horizon (2^64) and diagonal transmission (√2 ).
Neutron-proton mass difference (∆_m): Modeled as potential energy stored in the geometric compression of the electron (icosahedron, 20 faces) into the protonic frame (cube, 8 vertices). Compression ratio = 20/8 = 5/2.
Gravitational constant (G) without G: Derived from quantum constants and the proton mass, identifying G as a scaling artifact of the 128-bit hierarchy (2^128).
Fine-structure constant (α): Derived as the static spatial cost plus a spinor loop correction.
Preprint: Geometric Unification of Physical Interactions
Comments URL: Is the Standard Model overfitting or am I curve-fitting? | Hacker News
Points: 3
# Comments: 18
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Results:
Proton radius (r_p): Modeled as a tetrahedral structural limit (4 · ƛ) with spherical field projection loss (α / 4 · π).
Code:
r_p = 4 · ƛ_p · (1 - (α / (4 · π)))
Pred: 8.407470 × 10^-16 m
Exp: 8.4075(64) × 10^-16 m
Diff: 3 ppm
Code:
g_p = (δ^3 / w) - (α / Φ)
Pred: 5.5856599
Exp: 5.5856947
Diff: 6 ppm
Code:
a_μ = (α / (2 · π)) + (α^2 / 12) + (α^3 / 5)
Pred: 0.00116592506
Exp: 0.00116592059
Diff: 4 ppm
Code:
r_α = 8 · ƛ_p · (1 - (α / π))
Pred: 1.67856 × 10^-15 m
Exp: 1.678 × 10^-15 m
Diff: 330 ppm
Code:
m_p = ((√2 · m_P) / 2^64) · (1 + α / 3)
Pred: 1.67260849206 × 10^-27 kg
Exp: 1.67262192595(52) × 10^-27 kg
Diff: 8 ppm
Code:
∆_m = m_e · ((5/2) + 4 · α + (α / 4))
Pred: 1.293345 MeV
Exp: 1.293332 MeV.
Diff: 10 ppm.
Code:
G = (ħ · c · 2 · (1 + α / 3)^2) / (m_p^2 · 2^128)
Pred: 6.6742439706 × 10^-11
Exp: 6.67430(15) × 10^-11 m^3 · kg^-1 · s^-2
Diff: 8 ppm
Code:
α^-1 = (4 · π^3 + π^2 + π) - (α / 24)
Pred: 137.0359996
Exp: 137.0359991
Diff: < 0.005 ppm
Comments URL: Is the Standard Model overfitting or am I curve-fitting? | Hacker News
Points: 3
# Comments: 18
Continue reading...